0=-12t^2+60t

Solution for 0=-12t^2+60t equation:

0=-12t^2+60t

We move all terms to the left:

0-(-12t^2+60t)=0

We add all the numbers together, and all the variables

-(-12t^2+60t)=0

We get rid of parentheses

12t^2-60t=0

a = 12; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·12·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*12}=\frac{0}{24}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*12}=\frac{120}{24}
=5
$